Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The graph between $\sqrt{E}$ and $\frac{1}{p}$ is ( $E$ =kinetic energy and p = momentum)
Text Solution
Verified by ExpertsThe correct answer is:
C
$P = \sqrt{2 m E}$ it is clear that $P \propto \sqrt{E}$
So, the graph between P and $\sqrt{\mathcal{E}}$ will be straight line.
but graph between $\frac{1}{P}$ and $\sqrt{E}$ will be hyperbola
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